How do you write $y=x^2+26x+68$ in vertex form?

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Answer 1 · 2017-10-10T11:20:06

Vertex form of equation is $y=(x+13)^2-101$

$y= x^2+26x+68 or y= x^2+26x+169-169+68$ or

$y=(x+13)^2-101$ . Comparing with vertex form of equation

$y=a(x-h)^2+k ; (h,k)$ being vertex we find here

$h=-13 , k=-101$ . So vertex is at $(-13,-101)$ and vertex

form of equation is $y=(x+13)^2-101$ [Ans]

How do you write y=x^2+26x+68y=x^2+26x+68 in vertex form?