How do you write $y=x^2-2x+1$ into vertex form?

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Answer 1 · 2015-04-30T12:46:09

The vertex form of a quadratic function is given by
$y = a(x - h)^2 + k$ , where $(h, k)$ is the vertex of the parabola.

We can use the process of Completing the Square to get this into the Vertex Form.

$y=x^2-2x+1$

$-> y - 1 = x^2 - 4x$ (Transposed 1 to the Left Hand Side)

Now we ADD $4$ from each side to complete the square

$-> y - 1 + 4 = x^2 - 4x + 2^2$

$-> y + 3 = (x-2)^2$

$-> color(green)( y =1* (x-2)^2 - 3$ is the Vertex Form

The vertex of the Parabola is ${2 , -3}$

How do you write y=x^2-2x+1y=x^2-2x+1 into vertex form?