How do you write $y = x^2 - 2x -3$ into vertex form?

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Answer 1 · 2015-06-01T16:59:01

x of vertex: $x = (-b/2a) = 2/2 = 1$

y of vertex: $y = (f(1) = 1 - 2 - 3 = -4$

Vertex form: $f(x) = (x - 1)^2 - 4$

Check by developing: $f(x) = x^2 - 2x + 1 - 4$ . OK

How do you write y = x^2 - 2x -3y = x^2 - 2x -3 into vertex form?