Question

How do you write `y=x^2-6x+11` in vertex form?

Answer 1

`y = (x - 3)^2 + 2`

Explanation:

x-coordinate of vertex:
`x = -b/(2a) = 6/2 = 3`
y-coordinate of vertex:
y(3) = 9 - 18 + 11 = 2
Vertex (3, 2)
Vertex form of y:
`y = (x - 3)^2 + 2`