How do you write $y = x^{2} - 9 x - 10$ $y = x^2 - 9x - 10$ into vertex form?

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Answer 1 · 2018-04-18T17:41:26

$(y + \frac{121}{4}) = {(x - \frac{9}{2})}^{2}$ $(y+121/4)=(x-9/2)^2$

$y = x^{2} - 9 x - 10$ $" "y=x^2-9x-10$

$y = x^{2} - 2 \cdot \frac{9}{2} x + \frac{81}{4} - \frac{121}{4}$ $" "y=x^2-2*9/2x+81/4-121/4$

$y + \frac{121}{4} = x^{2} - 2 \cdot \frac{9}{2} x + \frac{81}{4}$ $" "y+121/4=x^2-2*9/2x+81/4$

$(y + \frac{121}{4}) = {(x - \frac{9}{2})}^{2}$ $" "(y+121/4)=(x-9/2)^2$

How do you write y = x^2 - 9x - 10y=x2−9x−10y = x^2 - 9x - 10 into vertex form?