How does #(1-sqrt(2/2))/(sqrt(2/2))# simplify to #-sqrt2+1#?

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Answer 1 · 2015-12-03T05:41:44

It doesn't. #(1-sqrt(2/2))/(sqrt(2/2))=0#

#(1-sqrt(2/2))/(sqrt(2/2))#

Simplify #2/2# to #1#.

#(1-sqrt1)/(sqrt1)#

Simplify.

#sqrt1=1#

#(1-1)/1=#

#0/1=#

#0#