How does instantaneous rate of change differ from average rate of change?

1 Answer
Aug 4, 2014

Instantaneous rate of change is essentially the value of the derivative at a point; in other words, it is the slope of the line tangent to that point. Average rate of change is the slope of the secant line passing through two points; it gives the average rate of change across an interval.

Below is a graph showing a function, #f(x)#, and the secant line across an interval #[2, 4]#. The slope of this secant line, which is

#(Deltay)/(Deltax) = (f(4) - f(2))/(4 - 2)#

is the average rate of change of #f(x)#.

http://sci.tamucc.edu/~jgiraldo/calculus1/classesguidelines/18DerivativeDefinition/DerivativeDefinitionv07.html

Below is a graph showing the function #f(x) = x^2#, as well as the line tangent at #x = 2#. The slope of this line is:

#dy/dx = f'(2) = 2*2 = 4#,

and it is the instantaneous rate of change at the point #(2,4)#.

http://sci.tamucc.edu/~jgiraldo/calculus1/classesguidelines/18DerivativeDefinition/DerivativeDefinitionv07.html