How many grams of calcium carbide are produced when 4.0 moles of carbon react with an excess of calcium carbonate (CaCO3)?

1 Answer
Truong-Son N.
Mar 19, 2018

Refer back to...

https://socratic.org/questions/how-do-you-do-a-through-e-1

And I hereby copy and paste.

We are told that #"CaCO"_3# is in excess, so clearly, #"C"# is the limiting reactant. Therefore, since #"5 mols C"# form #"2 mols CaC"_2#, we scale the reaction down to get:

#4/5 xx (color(red)(2)"CaCO"_3(s) + color(red)(5)"C"("gr") stackrel(Delta" ")(->) color(red)(2)"CaC"_2(s) + color(red)(3)"CO"_2(g))#

Now we read directly from the re-scaled balanced reaction that:

#=> 4/5 xx "5 mols C"# forms #4/5 xx 2 = color(blue)(8/5 "mols CaC"_2)#.

If the molar mass of #"CaC"_2# is #"64.099 g/mol"#, how many grams of #"CaC"_2# involves #8/5"mols"# of it? Your answer must be larger than #"64.099 g"# to make physical sense.

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