How many number roots does the equation have $3 x^{2} - 6 x + 3 = 0$ $3x^2-6x+3=0$ ?

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Answer 1 · 2016-12-11T06:52:50

1 unique root

$3 x^{2} - 6 x + 3 = 0$ $3x^2 - 6x + 3 = 0$

$\Rightarrow 3 (x^{2} - 2 x + 1) = 0$ $=> 3(x^2 - 2x + 1) = 0$

$\Rightarrow x^{2} - 2 x + 1 = 0$ $=> x^2 - 2x + 1 = 0$

$\Rightarrow {(x - 1)}^{2} = 0$ $=> (x - 1)^2 = 0$

$\Rightarrow x = 1$ $=> x = 1$

The equation has 1 unique root

How many number roots does the equation have 3x^2-6x+3=03x2−6x+3=03x^2-6x+3=0?