How much 0.1N HCl will a tablet of 200 mg Mg(OH)2 neutralize?

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How much 0.1N HCl will a tablet of 200 mg Mg(OH)2 neutralize?

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Answer 1 · 2018-02-03T16:25:24

A volume of approx. $70 \cdot m L$ $70*mL$ ....

Explanation:

We need (i) a stoichiometric equation.....

$M {g (O H)}_{2} (s) + 2 H C l (a q) \to M g C l_{2} (a q) + 2 H_{2} O (l)$ $Mg(OH)_2(s) + 2HCl(aq) rarr MgCl_2(aq) + 2H_2O(l)$

And (ii), equivalent quantities of magnesium hydroxide...

$n_{magnesium hydroxide} = \frac{200 \times 10^{- 3} \cdot g}{58.32 \cdot g \cdot m o l^{- 1}} = 3.43 \times 10^{- 3} \cdot m o l$ $n_"magnesium hydroxide"=(200xx10^-3*g)/(58.32*g*mol^-1)=3.43xx10^-3*mol$ .

And finally we take the quotient....

$\frac{3.43 \times 10^{- 3} \cdot m o l}{\frac{1}{2} \times 0.10 \cdot m o l \cdot L^{- 1}} \times 1000 \cdot m L \cdot L^{- 1} = ? ? \cdot m L$ $(3.43xx10^-3*mol)/(1/2xx0.10*mol*L^-1)xx1000*mL*L^-1=??*mL$

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How much 0.1N HCl will a tablet of 200 mg Mg(OH)2 neutralize?

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