Question

How much 0.1N HCl will a tablet of 200 mg Mg(OH)2 neutralize?

Answer 1

A volume of approx. `70*mL`....

Explanation:

We need (i) a stoichiometric equation.....

`Mg(OH)_2(s) + 2HCl(aq) rarr MgCl_2(aq) + 2H_2O(l)`

And (ii), equivalent quantities of magnesium hydroxide...

`n_"magnesium hydroxide"=(200xx10^-3*g)/(58.32*g*mol^-1)=3.43xx10^-3*mol`.

And finally we take the quotient....

`(3.43xx10^-3*mol)/(1/2xx0.10*mol*L^-1)xx1000*mL*L^-1=??*mL`