How to calculate derivative? (7x-1)^3(2x+1)^2(7x−1)3(2x+1)2

1 Answer
Manikandan S.
Nov 22, 2017

Explanation:

y = (7x-1)^3(2x+1)^2y=(7x−1)3(2x+1)2
y' =3(7x-1)^2\times 7\times(2x+1)^2+(7x-1)^3\times2(2x+1)\times2
y' = (7x-1)^2(2x+1)\times{21(2x+1)+4(7x-1)}
y' = (7x-1)^2(2x+1)\times{42x+21+28x-4}
y' = (7x-1)^2(2x+1)(70x+17)

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