How to calculate derivative? #(7x-1)^3(2x+1)^2#

1 Answer
Manikandan S.
Nov 22, 2017

Explanation:

#y = (7x-1)^3(2x+1)^2#
#y' =3(7x-1)^2\times 7\times(2x+1)^2+(7x-1)^3\times2(2x+1)\times2#
#y' = (7x-1)^2(2x+1)\times{21(2x+1)+4(7x-1)}#
#y' = (7x-1)^2(2x+1)\times{42x+21+28x-4}#
#y' = (7x-1)^2(2x+1)(70x+17)#

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