An engine of a train moving with uniform acceleration passes an electric pole with velocity u and last compartment with velocity v. The middle point of the train passes past the same pole with a velocity of?

1 Answer
Jun 15, 2017

The velocity is =u2+v22

Explanation:

Let the length of the train be =l

We apply the equation of motion

v2=u2+2al

2al=v2u2

The acceleration is a=v2u22l

For, half the train, the length is =l2 and the

velocity is =w

Therefore,

w2=u2+2al2

=u2+al

=u2+v2u22ll

=2u2+v2u22

=u2+v22

So,

w=u2+v22