How to factorise (x+5)(x+9)(x+3)(x+7)33?

1 Answer
Jun 4, 2018

(x+5)(x+9)(x+3)(x+7)33

=(x+3)(x+9)(x+7)(x+5)33

=[x(x+9)+3(x+9)][x(x+5)+7(x+5)]33

=[x2+9x+3x+27][x2+5x+7x+35]33

=[x2+12x+27][x2+12x+35]33

=[a+27][a+35]33

=a(a+35)+27(a+35)33

=a2+35a+27a+94533

=a2+62a+912

=a2+24a+38a+912

=a(a+24)+38(a+24)

=(a+24)(a+38)=[x2+12x+24][x2+12x+38]