How to solve for x? : 8*2^2x+4*2^x+1=1+2^x

1 Answer
Apr 27, 2018

x cannot be solved.

Explanation:

822x+42x+1=1+2x

Subtract 1 from both sides,

822x+42x=2x

Subtract 2x from both sides,

822x+32x=0

Apply the power of a power law, where (an)m=anm,

8(2x)2+32x=0

Let 2x be u,

8u2+3u=0

Factor,

u(8u+3)=0

Solve,

u=0or38

When u=0,

2x=0 ( No solution as 2x cannot be 0 )

When u=38,

2x=38 ( No solution as 2x cannot be negative )

Hence, x cannot be solved.