How to you find the general solution of $dy/dx=xe^(x^2)$ ?

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Answer 1 · 2016-11-23T21:14:40

$y = 1/2e^(x^2) + c$

This is a First Order Separable DE, so we can just separate the variable in it's current form to give;

$int dy = int xe^(x^2) dx$

And note we can re-write as:

$int dy = 1/2int 2xe^(x^2) dx$

So we can integrate to give:

$y = 1/2e^(x^2) + c$

How to you find the general solution of dy/dx=xe^(x^2)dy/dx=xe^(x^2)?