How to you find the general solution of $yy'=6cos(pix)$ ?

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Answer 1 · 2017-01-26T01:36:16

$y(x) = +-sqrt(12/pi sin(pix)+C)$

Separate the variables in the equation:

$y (dy)/(dx) = 6cos(pix)$

$y dy = 6cos(pix) dx$

integrate now both sides:

$int y dy = 6 int cos(pix) dx$

$y^2/2 = 6/pi sin(pix) + C$

$y(x) = +-sqrt(12/pi sin(pix)+C)$

How to you find the general solution of yy'=6cos(pix)yy'=6cos(pix)?