The price of a stock, A(x), over a 12-month period decreased and then increased according to the equation... ?

Question

The price of a stock, A(x), over a 12-month period decreased and then increased according to the equation, A(x)= $0.75 x^{2} - 6 x + 20$ $0.75x^2−6x+20$ , where x equals the number of months. The price of another stock, B(x), increased according to the equation B(x)= 2.75x+1.50 over the same 12-month period. Graph and label both equations on the accompanying grid. State all prices, to the nearest dollar, when both stock values were the same.

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Answer 1 · 2018-07-29T05:57:15

The stock values are the same for $= $ 9$ $=$9$ and $= 30 $$ $=30$$

Plot the graph of

$A (x) = 0.75 x^{2} - 6 x + 20$ $A(x)=0.75x^2-6x+20$

graph{0.75x^2-6x+20 [-10.33, 40.98, -3.18, 22.5]}

Then plot

$B (x) = 2.75 x + 1.50$ $B(x)=2.75x+1.50$

graph{2.75x+1.50 [-13.7, 51.24, -0.84, 31.67]}

Then,

plot the graphs on the same plot

graph{(y-0.75x^2+6x-20)(y-2.75x-1.50)=0 [-6.92, 33.61, 6.85, 27.16]}

The points of intersections are

$C = (2.774, 9.128)$ $C=(2.774,9.128)$

and

$D = (8.893, 29.956)$ $D=(8.893,29.956)$