Identities, Please Help??

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1 Answer
May 5, 2018

Please see the explanation below.

Explanation:

"Question (a)"Question (a)

arcsin(x^2-1)=1/3piarcsin(x21)=13π

sin(1/3pi)=x^2-1sin(13π)=x21

x^2-1=sqrt3/2x21=32

x^2=(sqrt 3/2+1)x2=(32+1)

x=+-sqrt((sqrt 3/2+1))=+-1.366x=± (32+1)=±1.366

"Question (b)"Question (b)

sin(2theta+1/3pi)=1/2sin(2θ+13π)=12

(2theta+1/3pi)=arcsin(1/2)(2θ+13π)=arcsin(12)

{(2theta+1/3pi=pi/6),(2theta+1/3pi=5/6pi), (2theta+1/3pi=13/6pi),(2theta+1/3pi=17/6pi):}

<=>, {(2theta=-1/3pi+pi/6=-1/3pi),(2theta=-1/3pi+5/6pi=pi/2), (2theta=-1/3pi+13/6pi=11/6pi),(2theta=-1/3pi+17/6pi=5/2pi):}

<=>, {(theta=-1/6pi),(theta=pi/4), (theta=11/12pi),(theta=5/4pi):}

The solutions must be for x in [0, pi]

The solutions are

S={pi/4, 11/12pi}