"Question (a)"Question (a)
arcsin(x^2-1)=1/3piarcsin(x2−1)=13π
sin(1/3pi)=x^2-1sin(13π)=x2−1
x^2-1=sqrt3/2x2−1=√32
x^2=(sqrt 3/2+1)x2=(√32+1)
x=+-sqrt((sqrt 3/2+1))=+-1.366x=±
⎷(√32+1)=±1.366
"Question (b)"Question (b)
sin(2theta+1/3pi)=1/2sin(2θ+13π)=12
(2theta+1/3pi)=arcsin(1/2)(2θ+13π)=arcsin(12)
{(2theta+1/3pi=pi/6),(2theta+1/3pi=5/6pi), (2theta+1/3pi=13/6pi),(2theta+1/3pi=17/6pi):}
<=>, {(2theta=-1/3pi+pi/6=-1/3pi),(2theta=-1/3pi+5/6pi=pi/2), (2theta=-1/3pi+13/6pi=11/6pi),(2theta=-1/3pi+17/6pi=5/2pi):}
<=>, {(theta=-1/6pi),(theta=pi/4), (theta=11/12pi),(theta=5/4pi):}
The solutions must be for x in [0, pi]
The solutions are
S={pi/4, 11/12pi}