If $3 a + 1 = \frac{13}{3}$ $3a + 1= \frac { 13} { 3}$ , what is the value of $3 a - 3$ $3a - 3$ ?

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Answer 1 · 2018-04-06T07:55:54

The value of $3 a - 3$ $3a-3$ is $\frac{1}{3}$ $1/3$ .

To get $3 a - 3$ $3a-3$ , just subtract $4$ $4$ from both sides of the equation:

$3 a + 1 = \frac{13}{3}$ $3a+1=13/3$

$3 a + 1 - 4 = \frac{13}{3} - 4$ $3a+1color(blue)-color(blue)4=13/3color(blue)-color(blue)4$

$3 a - 3 = \frac{13}{3} - 4$ $3a-3=13/3color(blue)-color(blue)4$

$3 a - 3 = \frac{13}{3} - \frac{12}{3}$ $3a-3=13/3color(blue)-color(blue)(12/3)$

$3 a - 3 = \frac{13 - 12}{3}$ $3a-3=(13color(blue)-color(blue)12)/3$

$3 a - 3 = \frac{1}{3}$ $3a-3=1/3$

Hope this helped!

Answer 2 · 2018-04-06T07:58:45

$\Rightarrow \frac{1}{3}$ $color(indigo)(=>1/3$

$3 a + 1 = \frac{13}{3}$ $3a + 1 = 13/3$

$3 a = \frac{13}{3} - 1$ $3a = 13/3 - 1$

$3 a = \frac{13 - 3}{3} = \frac{10}{3}$ $3a = (13-3) / 3 = 10/3$

Subtracting 3 on both sides,

$3 a - 3 = \frac{10}{3} - 3 = \frac{10 - 9}{3} = \frac{1}{3}$ $3a - 3 = 10/3 - 3 = (10-9)/3 = 1/3$

If 3a+1=133 3a + 1= \frac { 13} { 3}, what is the value of 3a−33a - 3?