If $4^{x} = 7$ $4^x= 7$ , then what does $4^{- 2 x}$ $4^ (-2x)$ equal?

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Answer 1 · 2015-09-01T17:08:11

If $4^{x} = 7$ $4^x = 7$ then $4^{- 2 x} = \frac{1}{49}$ $4^(-2x) = 1/49$

$4^{x} = 7$ $4^x = 7$

$4^{- 2 x}$ $4^(-2x)$

$= \frac{1}{4^{2 x}}$ $= 1/4^(2x)$

$= \frac{1}{{(4^{x})}^{2}}$ $= 1/[(4^x)^2]$

$= \frac{1}{{(7)}^{2}}$ $= 1/(7)^2$

$= \frac{1}{49}$ $= 1/49$

If 4x=74^x= 7, then what does 4−2x4^ (-2x) equal?