If a ball is thrown downward from the top of a building with initial velocity of 10 "m"/"s" and strikes the ground with a speed of 60 "m"/"s", how tall is the building?

This is a differential equations class, so we are being asked to use integrals.

1 Answer
Apr 25, 2018

s=178m

Explanation:

For this type of question, the best thing is to use the equation

(V_f)^2=(V_i)^2+2as

Where V_f is final velocity, V_i is initial velocity, a is acceleration, and s is displacement.

From here, you can just put in the values and solve for s.

(60m/s)^2=(10m/s)^2+2(9.81m/s^2)*s

s=178m