If a ball is thrown downward from the top of a building with initial velocity of $10 "m"/"s"$ and strikes the ground with a speed of $60 "m"/"s"$ , how tall is the building?

Question

This is a differential equations class, so we are being asked to use integrals.

15642 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-25T15:02:38

$s=178m$

For this type of question, the best thing is to use the equation

$(V_f)^2=(V_i)^2+2as$

Where $V_f$ is final velocity, $V_i$ is initial velocity, $a$ is acceleration, and $s$ is displacement.

From here, you can just put in the values and solve for $s$ .

$(60m/s)^2=(10m/s)^2+2(9.81m/s^2)*s$

$s=178m$