If a rocket with a mass of 3500 tons vertically accelerates at a rate of # 1/5 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 14 seconds?

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Answer 1 · 2018-02-23T07:32:21

The power is #=98MW#

The mass of the rocket is #m=3500000kg#

The acceleration of the rocket is #a=1/5=0.2ms^-2#

The acceleration due to gravity is #=9.8ms^-2#

According to Newton's second Law, the net force on the rocket is

#F=m(a+g)=3500000*(9.8+0.2)=35000000N#

Assuming that the initial velocity of the rocket is #u=0ms^-1#

The velocity after #t=14s# is

#v=u+at=0+0.2*14=2.8ms^-1#

The power is

#P=Fv=35000000*2.8=98000000W=98MW#