If a rocket with a mass of #3500 tons # vertically accelerates at a rate of # 9/2 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 15 seconds?

1 Answer
Sep 25, 2016

Given
#M->"Mass of rocket"=3500*10^3kg#
#a->"Acceleration"=9/2=4.5m/s^2#

#g->"Acceleration due to gravity"=9.8m/s^2#

#"Velocity after ts "(v)=at#

#"Force applied"(F)=M(g+a)#

#"Power at t s"#

#P(t)=Fxxv=M(g+a)at#

Power #"at "t=15 s#

#P(15)=35xx10^5xx(9.8+4.5)xx4.5xx15W#
#= 3378.375xx10^6 W=3378.375"MW"#