If a rocket with a mass of #7 kg# vertically accelerates at a rate of # 3/2 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 6 seconds?

1 Answer
Jul 19, 2017

The power is #=94.5W#

Explanation:

We apply Newton's Second Law to find the force

#F=ma#

The mass is #m=7kg#

The acceleration is #a=3/2ms^-2#

The force is

#F=ma=7*3/2=21/2N#

We apply the equation of motion

#v=u+at#

to calculate the speed at #t=6s#

#v=0+3/2*6=9ms^-1#

The power is

#P=Fv#

#P=21/2*9=94.5W#