If $f (x) = 2 x^{2} - 4 x - 3$ $f(x)=2x^2- 4x -3$ and $g (x) = 2 x^{2} - 16$ $g(x)= 2x^2- 16$ how do you find f(x)+ g(x)?

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Answer 1 · 2017-06-06T12:16:58

$f (x) + g (x) = 4 x^{2} - 4 x - 19$ $f(x) +g(x)=4x^2-4x-19$

$f(x) =2x^2-4x-3 ; g(x) =2x^2-16 :. f(x) +g(x)= 2x^2-4x-3 + 2x^2-16 = 4x^2-4x-19$
$f(x) +g(x)=4x^2-4x-19$
[Ans]

If f(x)=2x^2- 4x -3f(x)=2x2−4x−3f(x)=2x^2- 4x -3 and g(x)= 2x^2- 16g(x)=2x2−16g(x)= 2x^2- 16 how do you find f(x)+ g(x)?