If $f (x) = 2 x + 8$ $f(x)=2x+8$ and $g (x) = 3 x - 2$ $g(x)=3x-2$ , how do you find $g (f (1))$ $g(f(1))$ ?

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If $f (x) = 2 x + 8$ $f(x)=2x+8$ and $g (x) = 3 x - 2$ $g(x)=3x-2$ , how do you find $g (f (1))$ $g(f(1))$ ?

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Answer 1 · 2017-01-31T14:16:51

$g (f (1)) = 28$ $g(f(1))=28$

Explanation:

To evaluate g(f(1)) , first evaluate f(1) and substitute result into g(x)

$\Rightarrow f (1) = (2 \times 1) + 8 = 10$ $rArrf(color(magenta)(1))=(2xx color(magenta)(1))+8=10$

$\Rightarrow g (f (1)) = g (10) = (3 \times 10) - 2 = 28$ $rArrg(f(1))=g(color(magenta)(10))=(3xxcolor(magenta)(10))-2=28$

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If $f (x) = 2 x + 8$ $f(x)=2x+8$ and $g (x) = 3 x - 2$ $g(x)=3x-2$ , how do you find $g (f (1))$ $g(f(1))$ ?

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If f(x)=2x+8f(x)=2x+8 and g(x)=3x−2g(x)=3x-2, how do you find g(f(1))g(f(1))?

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Explanation:

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If $f (x) = 2 x + 8$ $f(x)=2x+8$ and $g (x) = 3 x - 2$ $g(x)=3x-2$ , how do you find $g (f (1))$ $g(f(1))$ ?