If $f(x) = 4x -2$ and $g(x) = e^(3x-1)$ , what is $f'(g(x))$ ?

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Answer 1 · 2016-02-29T18:18:50

$f(g(x))=4e^(3x-1)-2$
$(f(g(x))'=12e^(3x-1) but f'(g(x))=4e^(3x-1)$

Use chain rule to find derivative i.e.(f(g(x))'=f'(g(x)) g'(x) but first find f(g(x)) then find the derivative.

If f(x) = 4x -2f(x) = 4x -2 and g(x) = e^(3x-1)g(x) = e^(3x-1), what is f'(g(x)) f'(g(x)) ?