If $f (x) = 4 x - 2$ $f(x) = 4x -2$ and $g (x) = e^{- x - 1}$ $g(x) = e^(-x-1)$ , what is $f'(g(x))$ ?

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Answer 1 · 2017-04-16T01:21:08

$f'(g(x))=4$

First, take the derivative of $f(x)$ :

$f'(x)=4$

Now plug in $g(x)$ in for $x$ in $f'(x)$ . However, there's no $x$ . So that means that:

$f'(g(x))=4$

If f(x) = 4x -2f(x)=4x−2f(x) = 4x -2 and g(x) = e^(-x-1)g(x)=e−x−1g(x) = e^(-x-1), what is f'(g(x)) f'(g(x)) ?