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If $f (x) = x^{2} - x$ $f(x)= x^2-x$ and $g (x) = 3 x^{\frac{2}{3}}$ $g(x) = 3x^( 2/3 )$ , what is $f'(g(x))$ ?

1 Answer

Sep 16, 2016

$f'(g(x))=6x^(2/3)-1$

Explanation:

$f'(x)=2x-1$
$f'(g(x))=2(g(x))-1$
$f'(g(x))=2(3x^(2/3))-1$
$f'(g(x))=6x^(2/3)-1$

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