If xcos alpha+ysin alpha=xcos beta+ysin beta=kxcosα+ysinα=xcosβ+ysinβ=k then show that x/cos ((alpha+beta)/2)=y/sin ((alpha+beta)/2)=k/cos ((alpha-beta)/2)xcos(α+β2)=ysin(α+β2)=kcos(α−β2)?
1 Answer
Oct 22, 2017
Given
To show that
On cross multiplication of [1] an[2] we get