In a pile of nickels and dimes, the number of nickels is three times the number of dimes. If the pile is worth $1.75, how many nickels are there?

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Answer 1 · 2017-11-06T02:09:15

21 nickels.

Let $x$ $x$ be the number of dimes.
Let $3 x$ $3x$ be the number of nickels.

$0.10 (x) + 0.05 (3 x) = 1.75$ $0.10(x) + 0.05(3x) = 1.75$

Distribute $0.05$ $0.05$ :
$0.1 x + 0.15 x = 1.75$ $0.1x+0.15x=1.75$

Collect like terms:
$0.25 x = 1.75$ $0.25x=1.75$

Divide both sides by $0.25$ $0.25$ :
$x = 7$ $x=7$

$3 x = 21$ $3x = 21$

Therefore, there are 7 dimes and 21 nickels in the pile.