In navigation, a bearing is the angle.....?

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In navigation, a bearing is the angle.....?

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Answer 1 · 2018-07-01T04:23:22

$10^{\circ}$ $10^@$

Explanation:

I believe this is the right answer:

The ship's bearing is $80^{\circ}$ $80^@$ , which is the measure between the $y$ $y$ -axis and the terminal side.

Standard angles are angles that start at the origin and have the $x$ $x$ -axis as the terminal side. We know we are in quadrant one.

We know in the quadrant is $90^{\circ}$ $90^@$ . $80^{\circ}$ $80^@$ are already being taken up by the ship's bearing, so we can subtract these two. We get

$10^{\circ}$ $10^@$ . This represents the angle in standard position.

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In navigation, a bearing is the angle.....?

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