Question

In triangle ABC, <A=84.2°, <B=20.7°, B=17.2 how do you find side C?

Answer 1

c= 47.068

Angle C= 180- 84.2-20.7= 75.1 degrees. Now use Sin rule `sinB/b= SinC/c`

c= `b(sinC)/SinB` = `17.2 Sin 75.1/Sin 20.7`

=`17.2(0.966/0.353)`

= 47.068