Is 2pi*sqrt(l/g) reducable to a dimension of time?

1 Answer
Mar 18, 2016

Yes. Yes it is.

Explanation:

This equation is the period of a simple pendulum. Assuming your l stands for length, and g stands for gravity, we can rewrite this problem as

Period = 2pi*sqrt(L/(L/T^2))

Rewriting your fraction inside the sqrt() symbol,

Period =2pi*sqrt(L*T^2/L)

Cancelling terms and knowing that square roots cancel powers of 2, we get,

Period =2pi*T

So yes, this equation is reducible to a unit of time.