Is $2pi*sqrt(l/g)$ reducable to a dimension of time?

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Answer 1 · 2016-03-18T13:21:53

Yes. Yes it is.

This equation is the period of a simple pendulum. Assuming your $l$ stands for length, and $g$ stands for gravity, we can rewrite this problem as

Period $= 2pi*sqrt(L/(L/T^2))$

Rewriting your fraction inside the $sqrt()$ symbol,

Period $=2pi*sqrt(L*T^2/L)$

Cancelling terms and knowing that square roots cancel powers of 2, we get,

Period $=2pi*T$

So yes, this equation is reducible to a unit of time.

Is 2pi*sqrt(l/g)2pi*sqrt(l/g) reducable to a dimension of time?