Is #a^2-b^2# equal to #(a-b)(a+b)#?
2 Answers
Yes!
This is one that is really worth committing to memory. It crops up quite often.
Explanation:
Given:
Multiply everything in the right bracket by everything in the left
But
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Thus
Explanation:
#a^2-b^2" is called a "color(blue)"difference of squares"#
#"since "a^2" and "b^2" are perfect squares separated by a"#
#"difference (-)"#
#"to verify this result expand the factors"#
#rArr(color(red)(a-b))(a+b)#
#=color(red)(a)(a+b)color(red)(-b)(a+b)larrcolor(blue)"distribute"#
#=a^2cancel(+ab)cancel(-ab)-b^2#
#=a^2-b^2#
#"Useful factoring tool " color(red)(bar(ul(|color(white)(2/2)color(black)(a^2-b^2=(a-b)(a+b))color(white)(2/2)|)))#