Is $h (x) = \sqrt{x} \times (\sqrt{x} - 1)$ $h(x) = sqrt{x} times (sqrt{x} - 1)$ a polynomial function and if so what is the degree?

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Is $h (x) = \sqrt{x} \times (\sqrt{x} - 1)$ $h(x) = sqrt{x} times (sqrt{x} - 1)$ a polynomial function and if so what is the degree?

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Answer 1 · 2016-08-16T14:11:40

No, it is not a polynomial function. See explanation.

Explanation:

To find if it is a polynomial first we have to write the function s a sum of terms. To do so we have to multiply:

$h (x) = \sqrt{x} \times (\sqrt{x} - 1) = x - \sqrt{x}$ $h(x)=sqrt(x)xx(sqrt(x)-1)=x-sqrt(x)$

In a polynomial only expressions like $x^{n}$ $x^n$ for natural $n$ $n$ are allowed. $h (x)$ $h(x)$ contains $\sqrt{x}$ $sqrt(x)$ so it is not a polynomial.

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Is $h (x) = \sqrt{x} \times (\sqrt{x} - 1)$ $h(x) = sqrt{x} times (sqrt{x} - 1)$ a polynomial function and if so what is the degree?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

Is h(x) = sqrt{x} times (sqrt{x} - 1)h(x)=√x×(√x−1)h(x) = sqrt{x} times (sqrt{x} - 1) a polynomial function and if so what is the degree?

1 Answer

Explanation:

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Is $h (x) = \sqrt{x} \times (\sqrt{x} - 1)$ $h(x) = sqrt{x} times (sqrt{x} - 1)$ a polynomial function and if so what is the degree?