Is the curve (x2a2)(y2b2)+2xy+3x+4y=7 has only 2 asymptotes parallel to coordinate axes?

1 Answer
May 25, 2017

See below.

Explanation:

Solving for x (using the Bashkara formula) we have

x=±(3+2y)+(3+2y)24(y2b2)(a2b2+4ya2y27)2(y2b2)

and solving for y we have

y=±(4+2x)+(4+2x)24(x2a2)(a2b2+3xb2x27)2(x2a2)

so we have four asymptotes:

y=±b and

x=±a

Attached a plot for a=1, b=2

enter image source here