Question

Mr. J has pennies, nickels, dimes, quarters, one dollar bills and five dollar bills?

Mr. J has pennies, nickels, dimes, quarters, one dollar bills and five dollar bills. There are twice as many nickels as pennies, twice as many dimes as nickels, three fewer quarters than dimes and the same number of one dollar bills and five dollar bills as there are nickels. The total value of the money he has is $93.82. How many dimes does he have?

Answer 1

Mr. J has `7` pennies, `7` nickels, `14` dimes, `25` quarters, `14` one dollar bills and `14` five dollar bills

Explanation:

Let Mr.J have `x` one dollar bills, `x` five dollar bills and `x` nickles.

As there are twice as many nickels as pennies, number of pennies is `x/2` and as there are twice as many dimes as nickles, we have `2x` dimes. As Mr.J has `3` fewer quarters than dimes, number of quarters he has is `2x-3`.

Now each quarter is `25` cents or `$0.25` or `1/4`, each dime is `10` cents or `$0.10` or `1/10`, each nickle is `5` cents or `$0.05` or `1/20` and each penny is `1` cent or `$0.01` or `1/100`.

Hence total amount is

`5x+x+(2x-3)xx1/4+2x xx1/10+x xx1/20+x/2xx1/100=93.82`

or `1/100[500x+100x+25(2x-3)+20x+5x+x/2]=93.82`

or `625x+x/2+50x-75=9382`

or `675x+x/2=9382+75=9457`

or `1351x=18914`

or `x=18914/1351=14`

Hence, Mr. J has `14/2=7` pennies, `7` nickels, `14` dimes, `14xx2-3=25` quarters, `14` one dollar bills and `14` five dollar bills