Paper airplane follows the path y=2x2+20x+1 where y represents the height of the paper airplane in feet and x represents the seconds it has traveled. what is the time before the airplane will reach 15 feet?

1 Answer
May 10, 2016

15 is the value of y, so we will solve as we would a regular quadratic equation.

Explanation:

15 = -2x^2 + 20x + 1#

0=2x2+20x14

x = b±b24ac2a

x=20±2024×2×142×2

x=20±2884

x=0.757or9.243

Therefore, the paper airplane will be at 15 feet 0.757 seconds and 9.243 seconds after its launch.

Hopefully this helps!