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Answer 1 · 2018-03-02T16:16:33

See below

$F = Q v B$ $F=QvB$
(F is force , Q is charge , v is velocity , B is magnetic field)

$F = m a$ $color (red)(F=ma)$

$\Rightarrow m a = Q v B$ $=>ma=QvB$

$\Rightarrow \frac{m a}{Q v} = B$ $=>(ma)/(Qv)=B$

$\Rightarrow \frac{m (\frac{v}{t})}{Q v} = B$ $=>(m(v/t))/(Qv)=B$

$\Rightarrow (m v) (Q v t) = B$ $=>(mv)(Qvt)=B$

$\Rightarrow \frac{\sqrt{m^{2} v^{2}}}{Q d} = B$ $=>sqrt (m^2v^2)/(Qd)=B$

$\Rightarrow \frac{\sqrt{2 m k}}{Q d} = B$ $=>sqrt (2mk)/(Qd)=B$
Hope it helps