Please solve this question??

enter image source here i use conservaion of energy bt still cant solve...

1 Answer
Feb 23, 2018

Option (d)

Explanation:

In position A

total energy E_A=(KE)_A+(PE)_A=(60-20)J=40JEA=(KE)A+(PE)A=(6020)J=40J

In position B

total energy E_B=(KE)_B+(PE)_B=(100+40)=140JEB=(KE)B+(PE)B=(100+40)=140J

Then in moving particle from Ato BAB the difference in total energy becomes DeltaE=E_B-E_A=(140-40)J=100J

So net work done by all forces in moving from AtoB will be 100J and hence option (d) is accepted.