Prove/verify the identities: #(cos(-t))/(sec(-t)+tan(-t)) = 1 + sint#?

Thanks in advance

1 Answer
Apr 6, 2018

See below.

Explanation:

Recall that #cos(-t)=cost, sec(-t)=sect#, as cosine and secant are even functions. #tan(-t)=-tant,# as tangent is an odd function.

Thus, we have

#cost/(sect-tant)=1+sint#

Recall that #tant=sint/cost, sect=1/cost#

#cost/(1/cost-sint/cost)=1+sint#

Subtract in the denominator.

#cost/((1-sint)/cost)=1+sint#

#cost*cost/(1-sint)=1+sint#

#cos^2t/(1-sint)=1+sint#

Recall the identity

#sin^2t+cos^2t=1.# This identity also tells us that

#cos^2t=1-sin^2t#.

Apply the identity.

#(1-sin^2t)/(1-sint)=1+sint#

Using the Difference of Squares,

#(1-sin^2t)=(1+sint)(1-sint).#

#((1+sint)cancel(1-sint))/cancel(1-sint)=1+sint#

#1+sint=1+sint#

The identity holds.