Question

Simplify into terms of sin and cos? (cos[x]+sec[x])^2

Answer 1

`(cosx+secx)^2=cos^2x+2+1/cos^2x`

Explanation:

`(cosx+secx)^2=(cosx+1/cosx)^2`

= `cos^2x+2xxcosx xx1/cosx+1/cos^2x`

= `cos^2x+2+1/cos^2x`