Solve for y in #y + 1/2 = -1/3(x+1/2)#?

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Answer 1 · 2015-04-07T05:44:33

The solution is #y=-1/3x-2/3#.

#y+1/2=-1/3(x+1/2)#

Perform the distributive property first.

#y+1/2=-1/3x-1/6#

Subtract #1/2# from both sides. The common denominator for #1/2#

and #1/6# is #6#. So #1/2*3/3=3/6#.

#y=-1/3x-1/6-3/6# =

#y=1/3x-4/6# =

Reduce #4/6# to #2/3#.

#y=-1/3x-2/3#

If this is supposed to be the slope-intercept equation for a line, the slope is #-1/3# and the y-intercept is #-2/3#.