Solve the equation ?

Question

$x (x + 2) (x^{2} - 1) = - 1$ $x(x+2)(x^2-1)=-1$

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Answer 1 · 2018-06-18T08:53:01

$x_{1} = x_{2} = \frac{1}{2} (- 1 + \sqrt{5})$ $x_1=x_2=1/2(-1+sqrt(5))$
$x_{3} = x_{4} = \frac{1}{2} (- 1 - \sqrt{5})$ $x_3=x_4=1/2(-1-sqrt(5))$

Your term is equal to
${(x^{2} + x - 1)}^{2} = 0$ $(x^2+x-1)^2=0$
from here you will get all Solutions.