Solve the given equation. Round to the nearest ten-thousandth, if necessary. ? 3e^x-11=6

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Answer 1 · 2018-05-07T13:58:34

the answer
#x=ln(17/3)=1.735#

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#3e^x-11=6#

#3e^x=17#

#e^x=17/3#

now we must take ln to both side

#ln(e^x)=ln(17/3)#

#x=ln(17/3)=1.735#