Solve the simultaneous equations y = √xx+2 and (y+xy+x)(y-xyx)=0 ?

1 Answer
Nov 18, 2017

(-1,1),(2,2)(1,1),(2,2)

Explanation:

y=sqrt(x+2)to(1)y=x+2(1)

(y+x)(y-x)=0larrcolor(blue)"factors of difference of squares"(y+x)(yx)=0factors of difference of squares

rArry^2-x^2=0to(2)y2x2=0(2)

color(blue)"substitute "y=sqrt(x+2)" into equation "(2)substitute y=x+2 into equation (2)

(sqrt(x+2))^2-x^2=0(x+2)2x2=0

>rArrx+2-x^2=0>x+2x2=0

"multiply through by "-1multiply through by 1

x^2-x-2=0larrcolor(blue)"in standard form"x2x2=0in standard form

"the factors of - 2 which sum to - 1 are +1 and - 2"the factors of - 2 which sum to - 1 are +1 and - 2

rArr(x+1)(x-2)=0(x+1)(x2)=0

"equate each factor to zero and solve for x"equate each factor to zero and solve for x

x+1=0rArrx=-1x+1=0x=1

x-2=0rArrx=2x2=0x=2

"substitute these values into equation "(1)substitute these values into equation (1)

x=-1toy=sqrt(-1+2)=1x=1y=1+2=1

x=2toy=sqrt(2+2)=2x=2y=2+2=2

"points of intersection are "(-1,1)" and "(2,2)points of intersection are (1,1) and (2,2)