Solve this: abs(2cos3x)=1|2cos3x|=1 ---> (x=... + ...)?
abs(2cos3x)=1|2cos3x|=1
Will it be: x=pi/9+2/3kpix=π9+23kπ AND x=-pi/9+2/3kpix=−π9+23kπ
OR ......
x=pi/9+1/3kpix=π9+13kπ AND x=-pi/9+1/3kpix=−π9+13kπ
Will it be:
OR ......
1 Answer
Apr 2, 2017
Explanation:
As
either
and
or
and