The base of an isosceles triangle is 12 cm and its perimeter is 38 cm. What is the area of the triangle?

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Answer 1 · 2018-03-03T12:18:58

Area of the isosceles triangle is $69.2$ $69.2$ sq.cm.

The base of the isosceles triangle is $b = 12$ $b=12$ cm and let $l$ $l$ be two

legs of the isosceles triangle. Perimeter of the isosceles triangle

is $P=b+2l or 38 = 12+2l :. 2l =38-12 or 2l=26$ or

$l=13$ cm. Legs of the isosceles triangle are $13$ cm each.

Area of the isosceles triangle is $A=b/4*sqrt(4*l^2-b^2)$ or

$A=12/4*sqrt(4*13^2-12^2)=3*sqrt 532 ~~ 69.2 (1dp)$ sq.cm

Area of the isosceles triangle is $69.2$ sq.cm. [Ans]