The electron in a hydrogen atom orbits a stationary proton at a distance of 5.3*10^-11 m at a speed of 2.2*10^6 m/s. What is (a) the period (b) the force on the electron?

1 Answer
A08
Mar 11, 2018

(a) Given radius of electron orbit around a stationary proton
#r=5.3*10^-11\ m#
Circumference of the orbit #=2pir=2pixx5.3*10^-11\ m#
Period #T# is time taken for the electron to make one cycle

#:.T=(2pixx5.3*10^-11)/(2.2*10^6 )=1.5xx10^-16\ s#

(b) Force on the electron in a circular orbit when in equilibrium #=0#. The Coulomb's Force of attraction between the electron and proton provides the centripetal force required for its circular motion.

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